# Question: 1 The probability of an employee being absent is greater

1. The probability of an employee being absent is greater than the probability that the employee is absent given that the employee is sick.

2. The probability that an employee is sick when it is known that the employee is absent is equal to the probability that an employee is absent when it is known that the employee is sick.

3. If the chance for an employee to be absent is greater than the chance for an employee to be sick, then A and S are dependent events.

4. If the chance for an employee to be absent is greater than the chance for an employee to be sick, then P (A | S) 7 P(S | A).

5. If she knows that P (A) = 0.20 and P (S) = 0.15, the administrator can find P(S | A).

6. If the event A is independent of the event S, then S is independent of A.

7. If A1 is independent of A2, then finding out that Employee 1 is absent increases the chance that Employee 2 is absent.

An administrator tracks absences among the staff working in an office. For each employee, define the events.

A = {employee is absent}

S = {employee is sick}

Let A1 and S1 refer to one employee and let A2 and S2 refer to another.

2. The probability that an employee is sick when it is known that the employee is absent is equal to the probability that an employee is absent when it is known that the employee is sick.

3. If the chance for an employee to be absent is greater than the chance for an employee to be sick, then A and S are dependent events.

4. If the chance for an employee to be absent is greater than the chance for an employee to be sick, then P (A | S) 7 P(S | A).

5. If she knows that P (A) = 0.20 and P (S) = 0.15, the administrator can find P(S | A).

6. If the event A is independent of the event S, then S is independent of A.

7. If A1 is independent of A2, then finding out that Employee 1 is absent increases the chance that Employee 2 is absent.

An administrator tracks absences among the staff working in an office. For each employee, define the events.

A = {employee is absent}

S = {employee is sick}

Let A1 and S1 refer to one employee and let A2 and S2 refer to another.

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