A 57Fe nucleus at rest emits a 14.0-keV photon. Use conservation of energy and momentum to deduce

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A 57Fe nucleus at rest emits a 14.0-keV photon. Use conservation of energy and momentum to deduce the kinetic energy of the recoiling nucleus in electron volts. (Use Mc2 = 8.60 x 10-9 J for the final state of the 57Fe nucleus.)

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Physics

ISBN: 978-1118486894

10th edition

Authors: David Young, Shane Stadler

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Question Posted: Jan 28, 2010 04:29 AM

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A 57Fe nucleus at rest emits a 14.0-keV photon. Use conservation of energy and momentum to deduce

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Since the total momentum Pnucleus Pphoton Also for the recoiling nucl...View the full answer

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