A 60-45-15 nodular iron has a 0.2 percent yield strength Sy with a mean of 49.0 kpsi,

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A 60-45-15 nodular iron has a 0.2 percent yield strength Sy with a mean of 49.0 kpsi, a standard deviation of 4.2 kpsi, and a guaranteed yield strength of 33.8 kpsi. What are the Weibull parameters θ and b?

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Probability And Statistics For Engineers And Scientists

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3rd Edition

Authors: Anthony Hayter

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Question Posted: Oct 30, 2009 05:24 AM

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A 60-45-15 nodular iron has a 0.2 percent yield strength Sy with a mean of 49.0 kpsi,

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Take the Weibull equation for the standard deviation x 0xo1 2b r1 1b2 and the mean equati...View the full answer

Probability And Statistics For Engineers And Scientists

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