A 0.25-kg object is suspended on a light spring of spring constant 49 N/m. The spring is then compressed to a position 15 cm above the stretched equilibrium position. How much more energy does the system have at the compressed position than at the stretched equilibrium position?
Answer to relevant QuestionsA 0.25-kg object is suspended on a light spring of spring constant 49 N/m and the system is allowed to come to rest at its equilibrium position. The object is then pulled down 0.10 m from the equilibrium position and ...A 0.50-kg mass oscillates in simple harmonic motion on a spring with a spring constant of 200 N/m. What are (a) The period and (b) The frequency of the oscillation? The displacement of an object is given by y = (5.0 cm) cos[(20π rad/s)t]. What are the object’s (a) Amplitude, (b) Frequency, and (c) Period of oscillation? (a) If the spring constant in a mass–spring system is halved, the new period is (1) 2, (2) √2, (3) 1/√2, (4) ½ times the old period. Why? (b) If the initial period is 2.0 s and the spring constant is reduced to 1/3 ...The forces acting on a simple pendulum are shown in Fig. 13.26. (a) Show that, for the small angle approximation (sin θ ≈ θ), the force producing the motion has the same form as Hooke’s law. (b) Show by analogy with ...
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