A 0.340 kg particle moves in an xy plane according to x(t) = 15.00 + 2.00t

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A 0.340 kg particle moves in an xy plane according to x(t) = – 15.00 + 2.00t – 4.00t3 and y(t) = 25.00 + 7.00t – 9.00t2 ,with x and y in meters and / in seconds. At t = 0.700s, what are

(a) The magnitude and

(b) The angle (relative to the positive direction of the x axis) of the net force on the particle, and

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Fundamentals of Physics

ISBN: 978-0471758013

8th Extended edition

Authors: Jearl Walker, Halliday Resnick

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Question Posted: Jan 08, 2011 02:33 AM

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A 0.340 kg particle moves in an xy plane according to x(t) = 15.00 + 2.00t

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To solve the problem we note that acceleration is the second time derivative of the position functio...View the full answer

Fundamentals of Physics

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