A biology experiment requires the preparation of a water bath at 37.0oC (body temperature). The temperature of the cold tap water is 22.0oC, and the temperature of the hot tap water is 55.0oC. If a student starts with 90.0 g of cold water, what mass of hot water must be added to reach 37.0oC?
Answer to relevant QuestionsA 5.00-g sample of aluminum pellets (specific heat capacity = 0.89 JoC-1g-1) and a 10.00-g sample of iron pellets (specific heat capacity = 0.45 JoC-1g-1) are heated to 100.0oC. The mixture of hot iron and aluminum is then ...Consider the reaction 2HCl(aq) + Ba(OH)2(aq) → BaCl2(aq) + 2H2O(l) ΔH = –118 kJ Calculate ΔH for the reaction N2H4(l) + O2(g) → N2(g) + 2H2O(l) given the following data: 2NH3(g) + 3N2O(g) → 4N2(g) + 3H2O(l) ΔH = –1010.kJ N2O(g) + 3H2(g) → N2H4(l) + H2O(l) ΔH = –317 kJ 2NH3(g) + ½O2(g) → ...Given the following data: P4(s) + 6Cl2(g) → 4PCl3(g) ΔH = –1225.6 kJ P4(s) + 5O2(g) → P4O10(s) ΔH = –2967.3 kJ PCl3(g) + Cl2(g) → PCl5(g) ΔH = –84.2 kJ PCl3(g) + ½ O2(g) → Cl3PO(g) ΔH = –285.7 ...Does the reaction in Exercise 70 or that in Exercise 71 produce more energy per kilogram of reactant mixture (stoichiometric amounts)? Reaction of exercise 70 3Al(s) + 3NH4ClO4(s) → Al2O3(s) + AlCl3(s) + 3NO(g) + ...
Post your question