(a) A filamentary loop carrying current I is bent to assume the shape of a regular polygon...
Question:
(a) A filamentary loop carrying current I is bent to assume the shape of a regular polygon of n sides. Show that at the center of the polygon where r is the radius of the circle circumscribed by the polygon.(b) Apply this to cases when n = 3 and n = 4 and see if your results agree with those for the triangular loop of Problem 7.8 and the square loop of Problem 7.10, respectively.(c) As n becomes large, show that the result of part (a) becomes that of the circular loop of Example7.3.
nl Н sin п 2ar
Step by Step Answer:
a Consider one side of the po...View the full answer
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The area of a circle is given by the formula: A = ?r^2 Where A is the area, ? is a mathematical constant (approximately 3.14), and r is the radius of the circle. The radius is the distance from the center of the circle to the edge. So for example, if the radius of a circle is 5 units, the area would be: A = ?(5^2) = ?(25) = 78.5 square units Here three friends went out to a restaurant and decided to have pizza for lunch. While they were waiting for their order, one of them stepped out to take a call but promised to return in two minutes. The waiter came and presented them with the menu, and they decided to order two 10-inch pepperoni pizzas. The waiter took their order and left. Just then, the third friend returned and asked what they had ordered. They explained that they had ordered two small pepperoni pizzas as they were only three of them and it would be enough for them. However, the third friend suggested that for the same price, they could get a large pizza that would be much bigger than the two small ones. He asked the waiter for a pen and paper and proceeded to calculate the area of the two small pizzas and compared it to the area of one large pizza. The friends were amazed at how the circle measurements worked and decided to change their order from two small pizzas to one large pizza.
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