A half-cell produced by dissolving copper in water produces an electrode potential of +0.32 V. Calculate the

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A half-cell produced by dissolving copper in water produces an electrode potential of +0.32 V. Calculate the amount of copper that must have been added to 1000 mL of water to produce this potential.

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Essentials of Materials Science and Engineering

ISBN: 978-1111576851

3rd edition

Authors: Donald R. Askeland, Wendelin J. Wright

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Question Posted: Apr 26, 2016 07:30 AM

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A half-cell produced by dissolving copper in water produces an electrode potential of +0.32 V. Calculate the

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From the Nernst equation with E 0 034 V and the molecula...View the full answer

Essentials of Materials Science and Engineering

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