Question: A hydrogen atom has an orbital angular momentum with a magnitude of 1057(h/2). (a) Determine the value of the quantum number for this atom.

A hydrogen atom has an orbital angular momentum with a magnitude of 10√57(h/2π).

(a) Determine the value of the quantum number ℓ for this atom.

(b) What is the minimum possible value of this atom's principal quantum number, n? Explain.

(c) If 10√57(h/2π) is the maximum orbital angular momentum this atom can have, what is its energy?

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