Question

A length of wire with a resistance R is cut into two equal-length segments. These segments are then twisted together to form a conductor half as long as the original wire.
(a) The resistance of the shortened conductor is (1) R/4, (2) R/2, (3) R. Explain your reasoning.
(b) If the resistance of the original wire is 27 μΩ and the wire is, instead, cut into three equal segments and then twisted together, what is the resistance of the shortened conductor?


$1.99
Sales0
Views77
Comments0
  • CreatedAugust 29, 2015
  • Files Included
Post your question
5000