# Question

A manufacturer designed an experiment to compare the differences between men and women with respect to the times they require to assemble a product. A total of 15 men and 15 women were tested to determine the time they required, on average, to assemble the product. The time required by the men had a standard deviation of 4.5 minutes, and the time required by the women had a standard deviation of 2.8 minutes. Do these data show that the amount of time needed by men is more variable than the amount of time needed by women? Use a = 0.05 and assume the times are approximately normally distributed.

a. Solve using the p-value approach.

b. Solve using the classical approach.

a. Solve using the p-value approach.

b. Solve using the classical approach.

## Answer to relevant Questions

Ten subjects with borderline-high cholesterol levels were randomly recruited for a study that involved taking a nutrition education class. Cholesterol readings were taken before the class and 3 months after the class. Let d ...Use a computer or calculator to find the 95% confidence interval for estimating m d based on these paired data and assuming normality: State the null hypothesis, Ho, and the alternative hypothesis, Ha, that would be used to test these claims: a. The mean of the differences between the post-test and the pre-test scores is greater than 15. b. The mean ...Complete the hypothesis test with alternative Hypothesis m d ≠ 0 based on the paired data that follow and d = O – Y Use a = 0.01 Assume normality a. Solve using the p-value approach. b. Solve using the classical ...Two independent random samples resulted in the following: Sample A: nA = 24 sA = 8.5 Sample B: nB = 21 sB = 11.3 Find the estimate for the standard error for the difference between two means.Post your question

0