A parallel-plate capacitor with plate area A = 2.0m2 and plate separation d = 3.0mm is connected to a 35-V battery (Fig. 17-51a).

(a) Determine the charge on the capacitor, the electric field, the capacitance, and the energy stored in the capacitor.
(b) With the capacitor still connected to the battery, a slab of plastic with dielectric strength K = 3.2 is placed between the plates of the capacitor, so that the gap is completely filled with the dielectric (Fig. 17-51b).What are the new values of charge, electric field, capacitance, and the energy stored in the capacitor?

Transcribed Image Text:

A = 2.0 m2 d= 3.0 mm 35 V= 35 V= K = 3.2 3.0 mm