A potential difference V is applied to a wire of cross-sectional area A, length L, and resistivity
Question:
A potential difference V is applied to a wire of cross-sectional area A, length L, and resistivity p. You want to change the applied potential difference and stretch the wire so that the energy dissipation rate is multiplied by 30.0 and the current is multiplied by 4.00. Assuming the wire's density does not charge, what are
(a) The ratio of the new length to L and
(b) The ratio of the new cross-sectional area to A?
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We use P R pLA or LA Pip a The new values of L and ...View the full answer
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Related Book For
Fundamentals of Physics
ISBN: 978-0471758013
8th Extended edition
Authors: Jearl Walker, Halliday Resnick
Question Posted:
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