A random sample of 16 pharmacy customers showed the waiting times below (in minutes). Find a 90 percent confidence interval for, assuming that the sample is from a normal population.
Answer to relevant QuestionsA random sample of monthly rent paid by 12 college seniors living off campus gave the results below (in dollars). Find a 99 percent confidence interval for , assuming that the sample is from a normal population. Find the interval [μ– z σ / √ n μ + z σ / √ n] within which 90 percent of the sample means would be expected to fall, assuming that each sample is from a normal population. a. μ = 100, σ = 12, n = 36 b. μ = ...A sample of 50 homes in a subdivision revealed that 24 were ranch style (as opposed to colonial, tri-level, or Cape Cod). (a) Construct a 95 percent confidence interval for the true proportion of ranch style homes. (b) Check ...Last year, a study showed that the average ATM cash withdrawal took 65 seconds with a standard deviation of 10 seconds. The study is to be repeated this year. How large a sample would be needed to estimate this year's mean ...What sample size would be needed to estimate the true proportion of students at your college (if you are a student) who are wearing backpacks, with 95 percent confidence and an error of ±0.04?
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