A sample of ten items from a normal population had a mean of 300 and standard deviation of 10. Using these data, estimate a value for the random variable such that the probability is 0.95 that 90% of the measurements on this random variable will lie below the value.
Answer to relevant QuestionsSample of 25 measurements on a normally distributed quality characteristic has a mean of 85 and a standard deviation of 1. Using a confidence probability of 0.95, find a value such that 90% of the future measurements on this ...Find the sample size required to construct an upper nonparametric tolerance limit that contains at least 95% of the population with probability at least 0.95. How would this limit actually be computed from sample data? Consider the loan processing cycle time data in Exercise 8.15. Set up a CUSUM chart for monitoring this process. Does the process seem to be in statistical control? x p50 18.05; p84 20.53; p84 p50 ...Apply the scale CUSUM discussed in Section 9.1.8 to the data in Exercise 9.1 Exercise 9.1 Reconsider the data in Exercise 9.4. Set up an EWMA control chart with = 0.2 and L = 3 for this process. Interpret the results.. Assume = 0.05. CL = 0 = 8.02, UCL = 8.07, LCL = 7.97
Post your question