# Question

A senior manager, responsible for a group of 120 junior executives, is interested in the total amount of time per week spent by these people in internal meetings.

A random sample of 35 of these executives was asked to keep diary records during the next week. When the results were analyzed, it was found that these sample members spent a total of 143 hours in internal meetings.

The sample standard deviation was 3.1 hours.

Find a 90% confidence interval for the total number of hours spent in internal meetings by all 120 junior executives in the week.

A random sample of 35 of these executives was asked to keep diary records during the next week. When the results were analyzed, it was found that these sample members spent a total of 143 hours in internal meetings.

The sample standard deviation was 3.1 hours.

Find a 90% confidence interval for the total number of hours spent in internal meetings by all 120 junior executives in the week.

## Answer to relevant Questions

A simple random sample of 400 from a total 1,395 colleges in the United States maintained that 39 colleges use the text Statistics Made Difficult and Boring. Find a 95% confidence interval for the proportion of all colleges ...How large a sample is needed to estimate the population proportion for each of the following? a. ME = 0.03; α = 0.05 b. ME = 0.05; α = 0.05 c. Compare and comment on your answers to parts a and b. Determine the sample size needed for each of the following situations. a. N = 3,300 σ = 500 1.96σx-bar = 50 b. N = 4,950 σ = 500 1.96σx-bar = 50 c. N = 5,000,000 σ = 500 1.96σx-bar = 50 d. Compare and comment on your ...Find the reliability factor, zα/2, to estimate the mean, μ, of a normally distributed population with known population variance for the following. a. 93% confidence level b. 96% confidence level c. 80% confidence level Suppose that a survey of race fans at this week’s Daytona 500 NASCAR race were asked, Is this your first time attending the Daytona 500? From a random sample of 250 race fans, 100 answered in the affirmative. a. Find the ...Post your question

0