A solution is prepared by dissolving 0.5150 g of a solute (MW = 110.1) in 100.0 g
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A solution is prepared by dissolving 0.5150 g of a solute (MW = 110.1) in 100.0 g of an organic solvent (MW = 94.10). The solution is observed to have a freezing point 0.41°C below that of the pure solvent. A second solution is prepared by dissolving 0.4460 g of a solute having an unknown molecular weight in 95.60 g of the original solvent. A freezing point depression of 0.49°C is observed. Compute the molecular weight of the second solute and the heat of fusion (kJ/mol) of the solvent.
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x ATM 05150 g1101 gmol 05150 g1101 gmol 1000 g9410 gmol 201 RT2 m10 RT ...View the full answer
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Related Book For
Elementary Principles of Chemical Processes
ISBN: 978-0471720638
3rd Edition
Authors: Richard M. Felder, Ronald W. Rousseau
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