# Question: According to an IRS study it takes a mean of

According to an IRS study, it takes a mean of 330 minutes for taxpayers to prepare, copy, and electronically file a 1040 tax form. This distribution of times follows the normal distribution and the standard deviation is 80 minutes. A consumer watchdog agency selects a random sample of 40 taxpayers.

a. What is the standard error of the mean in this example?

b. What is the likelihood the sample mean is greater than 320 minutes?

c. What is the likelihood the sample mean is between 320 and 350 minutes?

d. What is the likelihood the sample mean is greater than 350 minutes?

a. What is the standard error of the mean in this example?

b. What is the likelihood the sample mean is greater than 320 minutes?

c. What is the likelihood the sample mean is between 320 and 350 minutes?

d. What is the likelihood the sample mean is greater than 350 minutes?

**View Solution:**## Answer to relevant Questions

A population consists of the following three values: 1, 2, and 3.a. Sampling with replacement, list all possible samples of size 2 and compute the mean of every sample.b. Find the means of the distribution of the sample mean ...At the downtown office of First National Bank, there are five tellers. Last week, the tellers made the following number of errors each: 2, 3, 5, 3, and 5.a. How many different samples of two tellers are possible?b. List all ...The mean amount purchased by a typical customer at Churchillâ€™s Grocery Store is $23.50, with a standard deviation of $5.00. Assume the distribution of amounts purchased follows the normal distribution. For a sample of 50 ...Use Appendix B.5 to locate the value of t under the following conditions.a. The sample size is 12 and the level of confidence is 95%.b. The sample size is 20 and the level of confidence is 90%.c. The sample size is 8 and the ...As a condition of employment, Fashion Industries applicants must pass a drug test. Of the last 220 applicants, 14 failed the test. Develop a 99% confidence interval for the proportion of applicants who fail the test. Would ...Post your question