Question: Although the VSEPR model is correct in predicting that CH4
Although the VSEPR model is correct in predicting that CH4 is tetrahedral, NH3 is pyramidal, and H2O is bent, the model in its simplest form does not account for the fact that these molecules do not have exactly the same bond angles (, HCH is 109.5 degrees, as expected for a tetrahedron, but, HNH is 107.3 degrees and , HOH is 104.5 degrees). Explain these deviations from the tetrahedral angle.
Answer to relevant QuestionsDraw Lewis structures and predict the molecular structures of the following. (See Exercises 89 and 90.) a. OCl2, KrF2, BeH2, SO2 c. CF4, SeF4, KrF4 b. SO3, NF3, IF3 d. IF5, AsF5 Which of the above compounds have net dipole ...There are two possible structures of XeF2Cl2, where Xe is the central atom. Draw them, and describe how measurements of dipole moments might be used to distinguish among them. Predict the molecular structure for each of the following. (See Exercises 89 and 90.) a. BrFI2 b. XeO2F2 c. TeF2Cl3- For each formula, there are at least two different structures that can be drawn using the same central ...In molecules of the type X–O–H, as the electronegativity of X increases, the acid strength increases. In addition, if the electronegativity of X is a very small value, the molecule acts like a base. Explain these ...Use the LE model to describe the bonding in H2CO and C2H2. Carbon is the central atom in H2CO, and C2H2 exists as HCCH.
Post your question