# Question: Americans ate an average of 25 7 pounds of confectionary products

Americans ate an average of 25.7 pounds of confectionary products each last year and spent an average of $61.50 per person doing so. If the standard deviation for consumption is 3.75 pounds and the standard deviation for the amount spent is $5.89, find the following:

a. The probability that the sample mean confectionary consumption for a random sample of 40 American consumers was greater than 27 pounds

b. The probability that for a random sample of 50, the sample mean for confectionary spending exceeded $60.00

a. The probability that the sample mean confectionary consumption for a random sample of 40 American consumers was greater than 27 pounds

b. The probability that for a random sample of 50, the sample mean for confectionary spending exceeded $60.00

## Answer to relevant Questions

A recent study of the life span of portable compact disc players found the average to be 3.7 years with a standard deviation of 0.6 year. If a random sample of 32 people who own CD players is selected, find the probability ...Of the total population of the United States, 20% live in the northeast. If 200 residents of the United States are selected at random, find the probability that at least 50 live in the northeast. A random sample of enrollments in Pennsylvania’s private four-year colleges is listed here. Check for normality. A random sample of the number of farms (in thousands) in various states follows. Estimate the mean number of farms per state with 90% confidence. Assume σ = 31. If the variance of a national accounting examination is 900, how large a sample is needed to estimate the true mean score within 5 points with 99% confidence?Post your question