# Question: An ideal spring of force constant k is hung vertically

An ideal spring of force constant k is hung vertically from the ceiling, and a held object of mass m is attached to the loose end. You carefully and slowly ease that mass down to its equilibrium position by keeping your hand under it until it reaches that position.

(a) Show that the spring’s change in length is given by d = mg/k.

(b) Show that the work done by the spring is Wsp = m2g2/2k.

(c) Show that the work done by gravity is Wg = m2g2/2k.

Explain why these two works do not add to zero. Since the overall change in kinetic energy is zero, you might think they should, no?

(d) Show that the work done by your hand is Whand = m2g2/2k and that the hand exerted an average force of half the object’s weight.

(a) Show that the spring’s change in length is given by d = mg/k.

(b) Show that the work done by the spring is Wsp = m2g2/2k.

(c) Show that the work done by gravity is Wg = m2g2/2k.

Explain why these two works do not add to zero. Since the overall change in kinetic energy is zero, you might think they should, no?

(d) Show that the work done by your hand is Whand = m2g2/2k and that the hand exerted an average force of half the object’s weight.

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