At 25C and 101 kPa, 2 mol of a gas containing 35 mol% propylene in propane is
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At 25°C and 101 kPa, 2 mol of a gas containing 35 mol% propylene in propane is equilibrated with 0.1 kg of silica gel adsorbent. Using the equilibrium data of Figure, calculate the moles and composition of the gas adsorbed and the equilibrium composition of the gas not adsorbed.
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0.9 y = 1-x 0.8 0.7 x* = 0.365 - 0.635 0.6 0.5 S, g solid x* - P/(P + A) W = P+A =1 mmol 0.4 S, g solid 0.3 Stage Gas out G = (A + P) - 1 mmol y* = P/ (P + A) Gas in F = (A + P) = 2 mmol 0.2 ZF- P/ (A + P) = 0.5 0.1 0.1 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1.0 Mole fraction propane in adsorbate, x (a) Mole fraction propane in gas, y wnuqinb3
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Let y and x be the mole fractions of P in the vapor and ad...View the full answer
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