Calculate H for the reaction N2H4(l) + O2(g) N2(g) + 2H2O(l) given the following data: 2NH3(g)
Question:
N2O(g) + 3H2(g) → N2H4(l) + H2O(l) ΔH = –317 kJ
2NH3(g) + ½O2(g) → N2H4(l) + H2O(l) ΔH = 2143 kJ
H2(g) + ½O2(g) → H2O(l) ΔH = –286 kJ
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