Calculate the pH at the halfway point and at the equiva-lence point for each of the following
Question:
a. 100.0 mL of 0.10 M HC7H5O2 (Ka = 6.4 × 10–5) titrated with 0.10 M NaOH
b. 100.0 mL of 0.10 M C2H5NH2 (Kb = 5.6 × 10–4) titrated with 0.20 M HNO3
c. 100.0 mL of 0.50 M HCl titrated with 0.25 M NaOH
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a This is a weak acidstrong base titration At the halfway point to equivalence weak acid conjugate base so pH pK a always for a weak acidstrong base t...View the full answer
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