Compute the mean, median, and standard deviation for the homeownership rates given in Exercise 3.10.
In exercise

a. Compare the mean and median for the 3 years of data. Which value, mean or median, is more appropriate for these data sets? Explain your answers.
b. Compare the degrees of variability in homeownership rates over the 3 years.

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1985 1996 2002 1985 1996 2002 70.4 71.0 3.5 61.2 629 673 64.7 62.0 65.9 66.6 66.6 70.2 New Hampshie 65.5 65.0 69.5 54.2 55.0 580 New Jersey 63.6 64.5 69.0 69.0 71.6 70.3 75 75.6 Montana Nebraska Nevada 66.5 68.6 69.3 68.5 668 684 Arizona 62.3 64.6 67.2 New Mexico New York North Carolina 6.0 704 700 North Dakota 50.3 527 55.0 Connecticut Delaware Dist. of Columbia 374 404 44.1 67.2 67.1 687 62.7 69.3 71.7 51.0 50.6 57.4 710 714 73.0 60.6 682 702 676 742 75.0 69.9 728 67.9 69.2 72.0 70.5 68.4 69.4 61.5 63. 66.2 716 71.7 614 56.6 596 Georgia Hawaii Oregon Rhode Island South Carolina 72.0 72.9 77.3 South Dakota Tennessee Illinois 67.6 67.8 71.5 67.6 688 70.1 60.5 618 63.8 715 72.7 72.7 69.5 70.3 702 68.5 68.5 74.3 66.8 63. 67.0 75.9 74.3 17.0 63.8 68.2 72.0 73.2 68.0 72.8 68.5 732 73.5 Louisiana 737 76.5 739 Vermont Virginia Massachusetts 60.5 617 627Washington Michigan Minnesota Mississippi Missouri 70.7 733 76.0 70.0 75.4 77.3 69.6 730 4.8Wyoming 69.270.2 West Virginia Wisconsin