Copper metal reacts with nitric acid. Assume that the reaction is 3Cu(s) + 8HNO3(aq) 3Cu(NO3)2(aq) +
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3Cu(s) + 8HNO3(aq) → 3Cu(NO3)2(aq) + 2NO(g) + 4H2O(l)
If 6.01 g Cu(NO3)2 is eventually obtained, how many grams of nitrogen monoxide, NO, would have formed?
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