Denoting by A r the position vector of point A of a rigid slab that is in plane motion, show that

(a) The position vector C r of the instantaneous center of rotation is rC = rA + ω x vA/ω2 where ω is the angular velocity of the slab and A v is the velocity of point A,

(b) The acceleration of the instantaneous center of rotation is zero if, and only if, aA = α/ω vA + ω x vA where α = αk is the angular acceleration of the slab.

Transcribed Image Text:

O. .A C (0) a