Derive (15-44). Use this equation to solve the following problem. Sulfate ion is to be removed from
Question:
Derive (15-44). Use this equation to solve the following problem. Sulfate ion is to be removed from 60 L of water by exchanging it with chloride ion on 1 L of a strong-base resin with relative molar selectivities as listed in Table 15.6 and an ion-exchange capacity of 1.2 eq/L of resin. The water to be treated has a sulfate-ion concentration of 0.018eq/L and a chloride-ion concentration of 0.002eq/L. Following the attainment of equilibrium ion exchange, the treated water will be removed and the resin will be regenerated with 30 L of 10 wt% aqueous NaCl.
(a) Write the ion-exchange reaction.
(b) Determine the value of KSO2 –4, Cl–.
(c) Calculate equilibrium concentrations cSO2 –4, c,Cl– , q SO2 –4, and qCl– in eqL for the initial ion-exchange step.
(d) Calculate the concentration of C1– in eq/L for the regenerating solution.
(e) Calculate cSO2 –4, cCl–, q SO2 –4, and qCl- upon reaching equilibrium in the regeneration step.
(f) Are the separations sufficiently selective?
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