Determine the equilibrium constant KP for the process CO + ½ O2 = CO2 at (a) 298
Question:
(a) 298 K
(b) 2000 K.
Compare your results with the values for KP listed in Table A-28.
Transcribed Image Text:
TABLE A-28 Natural logarithms of the equilibrium constant K The equilibrium constant kp for the reaction AA+cC+D is defined as KpP P 298-164.005 -186.975 -367.480 500-92.827-105.630 213.372 1000-39.803 45.150-99.127 1200-30,874 35.005 -80.011 1400-24.463 27.742-66.329 1600 -19.637 22.285-56.055 1800-15.866 18.03048.051I 2000-12.84014.622-41.645 2200 -10.353 11.827 36.391 2400 8.276 9.497 -32.011 2600 -6.517 7.521-28.304 2800 5.002 5.826-25.117 3000 3.685.357 -22.359 3200 2.534 3.072-19.937 3400 1.516 1.935 -17.800 3600 0.609 0.926-15.898 3800 0.202 0.019-14.199 0.796 -12.660 2.513 9.414 3.895 6.807 5.023 4.666 5.963 -2.865 -92.208 -52.691 -23.163 -18.182 -106.208 -60.281 -26.034 -20.283 -16.099 -13.066 -10.657 -8.728 -103.762 -57.616 -23.529 -17.871 -35.052 -6.270 -11.921 -9.826 -8.497 -6.635 -3.931 -6.768 -5.832 -4.719 -3.860 -3.019 -2.671 -2.801 -2.937 -2.212 -3.086 -0.429 0.701 -1.513 -0.501 -0.044 -0.945 -0.542 0.312 0.996 0.934 2.486 4500 -0.921 -0.686 -0.497 -0.341 1 5500 4.743 2843 4.245
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Related Book For
Thermodynamics An Engineering Approach
ISBN: 978-0073398174
8th edition
Authors: Yunus A. Cengel, Michael A. Boles
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