Evaporation of sweat is an important mechanism for temperature control in some warm-blooded animals. (a) What mass
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(a) What mass of water must evaporate from the skin of a 70.0-kg man to cool his body 1.00 C°? The heat of vaporization of water at body temperature (37°C) is 2.42 X 106 J/kg. K. The specific heat of a typical human body is 3480J/kg· K (see Exercise 17.37).
(b) What volume of water must the man drink to replenish the evaporated water? Compare to the volume of a soft-drink can (355 cm3)
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IDENTIFY For a temperature change QmcAT For the liquid vapor phase change QmL SET UP The densi...View the full answer
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