Figure shows a case in which the momentum component p x of a particle is fixed so
Question:
Figure shows a case in which the momentum component px of a particle is fixed so that ∆px = 0; then, from Heisenberg's uncertainty principle (Eq. 38-20), the position x of the particle is completely unknown. From the same principle it follows that the opposite is also true; that is, if the position of a particle is exactly known (∆x = 0), the uncertainty in its momentum is infinite. Consider an intermediate case, in which the position of a particle is measured, not to infinite precision, but to within a distance of λ/2π, where λ is the particle's de Broglie wavelength. Show that the uncertainty in the (simultaneously measured) momentum component is then equal to the component itself; that is, ∆px = p. Under these circumstances, would a measured momentum of zero surprise you? What about a measured momentum of 0.5p of 2p of l2p?
Step by Step Answer:
We use the uncertainty relationship AxAp Letting Ax 2 the de Broglie wav...View the full answer
Probability & Statistics For Engineers & Scientists
ISBN: 9780130415295
7th Edition
Authors: Ronald E. Walpole, Raymond H. Myers, Sharon L. Myers, Keying
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