Find an equation of the tangent line to the curve at the given point. y = ln(x2

Question:

Find an equation of the tangent line to the curve at the given point.
y = ln(x2 - 3x + 1), (3, 0)
Fantastic news! We've Found the answer you've been seeking!

Step by Step Answer:

Related Book For  book-img-for-question
Question Posted: