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Answer to relevant QuestionsA hot-rolled 1035 steel has a 0.2 percent tensile yield strength Sy = LN (49.6, 3.81) kpsi. A round rod in tension is subjected to a load P = LN (30, 5.1) kip. If the rod diameter d is 1.000 in, what is the probability that ...Repeat Prob. 20–25, presuming the distribution is lognormal. What is the yield strength exceeded by 99 percent of the population? Compare the normal fit of Prob. 20–25 with the lognormal fit by superposing the PDFs and ...A 100-70-04 nodular iron has tensile and yield strengths described by Sut = W [47.6, 125.6, 11.84] kpsi Sy = W [64.1, 81.0, 3.77] kpsi What is the chance that Sut is less than 100 kpsi? What is the chance that Sy ...A 35018 malleable iron has a 0.2 percent offset yield strength given by the Weibull distribution Sy = W [34.7, 39.0, 2.93] kpsi. What are the mean, the standard deviation, and the coefficient of variation?Generally, final design results are rounded to or fixed to three digits because the given data cannot justify a greater display. In addition, prefixes should be selected so as to limit number strings to no more than four ...
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