Find the absolute maximum and absolute minimum values of f on the given interval. 47. f(x) =
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![47. f(x) = 3x? - 12x + 5. [0, 3] 48. f(x) = x - 3x + 1, [0, 3] 49. f(x) = 2x - 3x - 12x + 1. [-2, 3] 50. f(x) = x' – 6](https://dsd5zvtm8ll6.cloudfront.net/si.question.images/images/M-C-D(292).PNG)
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47 fx 3x 12x 5 03 fx 6x120 x2 Applying the Closed Interval Method we find that f0 5 f2 7 and f3 4 So f0 5 is the absolute maximum value and f2 7 is th...View the full answer
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