Find the min and max of the function on the given interval by comparing values at the
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25. y = 2x2 + 4x + 5, [−2, 2]
27. y = 6t − t2, [0, 5]
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25 Let f x 2x 2 4x 5 Then fx 4x 4 0 implies that x 1 is the only criti...View the full answer
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