Find the toughness (or energy to cause fracture) for a metal that experiences both elastic and plastic
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Find the toughness (or energy to cause fracture) for a metal that experiences both elastic and plastic deformation. Assume Equation 6.5 for elastic deformation, that the modulus of elasticity is 172GPa (25 ( 106psi), and that elastic deformation terminates at a strain of 0.01. For plastic deformation, assume that the relationship between stress and strain is described by Equation 6.19, in which the values for K and n are 6900MPa (1 ( 106psi) and 0.30, respectively. Furthermore, plastic deformation occurs between strain values of 0.01 and 0.75, at which point fracture occurs.
Transcribed Image Text:
%3D (6.5) Ee (6.19) T= Ke
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Related Book For
Fundamentals of Materials Science and Engineering An Integrated Approach
ISBN: 978-1118061602
4th Edition
Authors: David G. Rethwisch
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