Five measurements of the tar content of a certain kind of cigarette yielded 14.5, 14.2, 14.4, 14.3, and 14.6 mg/cigarette. Assuming that the data are a random sample from a normal population, use the four steps on page 354 to show that at the 0.05 level of significance the null hypothesis µ = 14.0 must be rejected in favor of the alternative µ ≠ 14.0.
Answer to relevant QuestionsWith reference to Exercise 13.30, use suitable statistical software to find the P-value that corresponds to the observed value of the test statistic. Use this P-value to rework the exercise. In exercise Five measurements of ...Rework Exercise 13.36, basing the decision on the P-value corresponding to the observed value of the test statistic. In exercise A study of the number of business lunches that executives in the insurance and banking ...In a study of the effectiveness of certain exercises in weight reduction, a group of 16 persons engaged in these exercises for one month and showed the following results: Use the 0.05 level of significance to test the null ...With reference to Example 13.5, test the null hypothesis σ1 – σ2 = 0 against the alternative hypothesis σ1 – σ2 > 0 at the 0.05 level of significance. With reference to Exercise 13.61, find the critical region and the actual level of significance corresponding to this critical region. In exercise In a random sample, 12 of 14 industrial accidents were due to unsafe working ...
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