# Question

For large numbers of degrees of freedom, we can approximate critical values of x2 as follows:

Here k is the number of degrees of freedom and z is the critical value(s) found from technology or table A-2. In Exercise 5 we have df = 35, so table A-4 does not list an exact critical value. If we want to approximate a critical value of x2 in the left-tailed hypothesis test with α = 0.05 and a sample size of 36, we let k = 35 with z = -1.645. Use this approximation to estimate the critical value of x2for Exercise 5. How close is it to the value of x2 = 22.465 obtained by using STATDISK and Minitab?

Here k is the number of degrees of freedom and z is the critical value(s) found from technology or table A-2. In Exercise 5 we have df = 35, so table A-4 does not list an exact critical value. If we want to approximate a critical value of x2 in the left-tailed hypothesis test with α = 0.05 and a sample size of 36, we let k = 35 with z = -1.645. Use this approximation to estimate the critical value of x2for Exercise 5. How close is it to the value of x2 = 22.465 obtained by using STATDISK and Minitab?

## Answer to relevant Questions

Repeat Exercise 19 using this approximation (with k and z as described in Exercise 19): A simple random sample of 81 births of Chinese babies resulted in a mean birth weight of 3245 g and a standard deviation of 466g. Test the claim that the standard deviation of birth weights of Chinese babies is equal to 567 ...Refer to the sample data in Exercise 1. a. What is the level of measurement of the data (nominal, ordinal, interval, ratio)? b. Are the values discrete or continuous? c. What does it mean to state that the sample is a simple ...In the largest clinical trial ever conducted, 401,974 children were randomly assigned to two groups. The treatment group consisted of 201,229 children given the Salk vaccine for polio, and the other 200,745 children were ...A study investigated survival rates for in-hospital patients who suffered cardiac arrest. Among 58,593 patients who had cardiac arrest during the day, 11,604 survived and were discharged. Among 28,155 patients who suffered ...Post your question

0