Question: For mercury at 1 atm the enthalpy of vaporization is
For mercury at 1 atm, the enthalpy of vaporization is 58.51 kJ/mol and the entropy of vaporization is 92.92 J K-1mol-1. What is the boiling point of mercury?
Answer to relevant QuestionsThe enthalpy of vaporization of ethanol is 38.7 kJ/ mol at its boiling point (78oC). Determine ΔSsys, ΔSsurr, and ΔSuniv when 1.00 mole of ethanol is vaporized at 78oC and 1.00 atm. The value of ΔGo for the reaction 2C4H10(g) + 13O2(g) → 8CO2(g) + 10H2O(l) is –5490. kJ. Use this value and data from Appendix 4 to calculate the standard free energy of formation for C4H10(g). Given the following data: 2C6H6(l) + 15O2(g) → 12CO2(g) + 6H2O(l) ΔGo = –6399 kJ C(s) + O2(g) → CO2(g) ΔGo = –394 kJ H2(g) + 1/2 O2(g) → H2O(l) ΔGo = –237 kJ calculate ΔGo for the reaction 6C(s) + 3H2(g) → ...Using data from Appendix 4, calculate ΔHo, ΔSo, and K (at 298 K) for the synthesis of ammonia by the Haber process: N2(g) + 3H2(g) ⇌ 2NH3(g) Calculate ΔG for this reaction under the following conditions (assume an ...Consider the following reaction at 298 K: 2SO2(g) + O2(g) → 2SO3(g) An equilibrium mixture contains O2(g) and SO3(g) at partial pressures of 0.50 atm and 2.0 atm, respectively. Using data from Appendix 4, determine the ...
Post your question