From the dichlorination of propane, four isomeric products with the formula C3H6Cl2 were isolated and designated A, B, C, and D. Each was separated and further chlorinated to give one or more trichloropropanes, C3H5Cl3. A and B gave three trichloro compounds, C gave one, and D gave two. Deduce the structures of C and D. One of the products from A was identical to the product from C. Deduce structures for A and B. (Hint: Start by drawing the structures of all four dichlorinated propane isomers.)