From the information below, identify element X.
a. The wavelength of the radiowaves sent by an FM station broadcasting at 97.1 MHz is 30 million (3.00 × 107) times greater than the wavelength corresponding to the energy difference between a particular excited state of the hydrogen atom and the ground state.
b. Let V represent the principal quantum number for the valence shell of element X. If an electron in the hydrogen atom falls from shell V to the inner shell corresponding to the excited state mentioned in part a, the wavelength of light emitted is the same as the wavelength of an electron moving at a speed of 570. m/s.
c. The number of unpaired electrons for element X in the ground state is the same as the maximum number of electrons in an atom that can have the quantum number designations n = 2, mℓ = –1, and ms = – 1/2
d. Let A represent the principal quantum number for the electron in an excited He+ ion in which the single electron has the same energy as the electron in the ground state of a hydrogen atom. This value of A also represents the angular momentum quantum number for the subshell containing the unpaired electron(s) for element X.

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