I showed that it is always possible to pick a vector potential whose divergence is zero (Coulomb
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I showed that it is always possible to pick a vector potential whose divergence is zero (Coulomb gauge). Show that it is always possible to choose ∆ ∙ A = – µ0ε0 (∂V/∂t), as required for the Lorentz gauge, assuming you know how to solve equations of the form 10.16. Is it always possible to pick V = 0, how about A = 0?
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