In Case Study 6.4, which examined maternal smoking and child’s IQ, one of the results reported in the journal article was the average number of days the infant spent in the neonatal intensive care unit. The results showed an average of 0.35 day for infants of nonsmokers and an average of 0.58 day for the infants of women who smoked 10 or more cigarettes per day. In other words, the infants of smokers spent an average of 0.23 day more in neonatal intensive care. A 95% confidence interval for the difference in the two means extended from 23.02 days to 12.57 days. Explain why it would have been misleading to report, “these results show that the infants of smokers spend more time in neonatal intensive care than do the infants of nonsmokers,” even though it was true for the infants in this study.
Answer to relevant QuestionsIn a study comparing age of death for left-and right-handed baseball players, Coren and Halpern (1991, p. 93) provided the following information: “Mean age of death for strong right-handers was 64.64 years (SD = 15.5, n = ...The 200 men in the sample had a mean height of 68.2 inches, with a standard deviation of 2.7 inches. The 200 women had a mean height of 63.1 inches, with a standard deviation of 2.5 inches. Assuming these were independent ...The Baltimore Sun (Haney, 21 February 1995) reported on a study by Dr. Sara Harkness in which she compared the sleep patterns of 6-month-old infants in the United States and the Netherlands. She found that the 36 U.S. ...For the research described in Case Study 6.2, the goal was to find out if eating breakfast cereal was associated with a reduction in body mass index ( BMI) for children (Frantzen et al., 2013). Although the analysis used by ...a. The participants in the study were five capuchin monkeys. To what population do you think the results apply? b. The researchers were interested in comparing the proportion of times the monkeys would cooperate by trading ...
Post your question