In Figure, a nonuniform bar is suspended at rest in a horizontal position by two massless cords.
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In Figure, a nonuniform bar is suspended at rest in a horizontal position by two massless cords. One cord makes the angle θ = 36.9° with the vertical; the other makes the angle Ф = 53.1° with the vertical. If the length L of the bar is 6.10 m, compute the distance x from the left end of the bar to its center of mass.
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The bar is in equilibrium so the forces and the torques acting on it each sum to zero Let T 1 be the ...View the full answer
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