In Problem 5-3, you drew the enantiomers for a number of chiral compounds. Now go back and
Question:
In problem 5.3
(a)
(b)
(c)
(d) 1-bromo-2-methylbutane
(e) chlorocyclohexane
(f) cis-1,2-dichlorocyclobutane
(g)
(h)
(i)
Transcribed Image Text:
OH pentan-2-ol он pentan-3-ol NH, CHCH COOH alanine CH,
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a b There is no asymmetric carbon in b c d e There is no asymme...View the full answer
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