In the spontaneous fission of lead-208, the following reaction occurs: 208Pb ( 129I + 76Cu + 31n

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In the spontaneous fission of lead-208, the following reaction occurs:
208Pb ( 129I + 76Cu + 31n
For every mole of lead-208 that decays, 0.1002 g of mass is lost. How much energy is given off per mole of lead-208 reacted?

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Introductory Chemistry version 1.0

ISBN: 978-1453327654

1st edition

Authors: David W. Ball

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Question Posted: Feb 28, 2016 05:17 AM

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In the spontaneous fission of lead-208, the following reaction occurs: 208Pb ( 129I + 76Cu + 31n

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Change in mass mass lost 01002 g This mass change ...View the full answer

Introductory Chemistry version 1.0

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