In this problem you will derive an expression for the potential energy of a segment of a
Question:
In this problem you will derive an expression for the potential energy of a segment of a string carrying a traveling wave (Figure). The potential energy of a segment equals the work done by the tension in stretching the string, which is ΔU = F(Δℓ - Δx),where F is the tension, Δx is the length of the stretched segment, and Δx is its original length. From the figure we see that
(a) Use the binomial expansion to show that Δℓ - Δx ≈ ½ (Δy/Δx)2 Δx, and therefore ΔU ≈ ½ F(Δy/Δx)2 Δx
(b) Compute dy/dx from the wave function in Equation. 15-13 and show that ΔU ≈ ½ Fk2 A2 cos2 (kx - wt)Δx.
(c) Use F = mv2 and v = w/k to show that your result for (b) is the same as Equation 15-16b.
1/2 Al x J(Ax)? + (Ay)? = Ar{1+(Ay/Ax)*}\"2
Step by Step Answer:
a For yx 1 l x1 12yx 2 So l x 12yx 2 xan...View the full answer
Fundamentals of Ethics for Scientists and Engineers
ISBN: 978-0195134889
1st Edition
Authors: Edmund G. Seebauer, Robert L. Barry
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