Question: In using the Kruskal Wallis test there is a correction factor

In using the Kruskal-Wallis test, there is a correction factor that should be applied whenever there are many ties: Divide H by
For each individual group of tied observations in the combined set of all sample data, calcu-late T = t3 — t, where t is the number of observations that are tied within the individual group. Find t for each group of tied values, then compute the value of T for each group, then add the T values to get ΣT. The value of Nis the total number of observations in all samples combined. Use this procedure to find the corrected value of H for Exercise 11. Does the cor-rected value of H differ substantially from the value found in Exercise 11 ?

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