# Question

Is lack of sleep causing traffic fatalities? A study conducted under the auspices of the National Highway Traffic Safety Administration found that the average number of fatal crashes caused by drowsy drivers each year was 1550 (BusinessWeek, January 26, 2004). Assume the annual number of fatal crashes per year is normally distributed with a standard deviation of 300.

a. What is the probability of fewer than 1000 fatal crashes in a year?

b. What is the probability the number of fatal crashes will be between 1000 and 2000 for a year?

c. For a year to be in the upper 5% with respect to the number of fatal crashes, how many fatal crashes would have to occur?

a. What is the probability of fewer than 1000 fatal crashes in a year?

b. What is the probability the number of fatal crashes will be between 1000 and 2000 for a year?

c. For a year to be in the upper 5% with respect to the number of fatal crashes, how many fatal crashes would have to occur?

## Answer to relevant Questions

The driving distance for the top 100 golfers on the PGA tour is between 284.7 and 310.6 yards (Golfweek, March 29, 2003). Assume that the driving distance for these golfers is uniformly distributed over this interval. a. ...The following data are from a simple random sample. 5 8 10 7 10 14 a. What is the point estimate of the population mean? b. What is the point estimate of the population standard deviation? A population has a mean of 200 and a standard deviation of 50. Suppose a simple random sample of size 100 is selected and is used to estimate μ. a. What is the probability that the sample mean will be within 5 of the ...The 10 most active stocks on the New York Stock Exchange on March 6, 2006, are shown here (The Wall Street Journal, March 7, 2006). Exchange authorities decided to investigate trading practices using a sample of three of ...A simple random sample of 50 items from a population with σ 6 resulted in a sample mean of 32. a. Provide a 90% confidence interval for the population mean. b. Provide a 95% confidence interval for the population mean. c. ...Post your question

0