Just one serving a month of kale or collard greens or more than two servings of carrots a week can reduce the risk of glaucoma by more than 60%, according to a UCLA study of 1000 women. Using a 90% confidence interval for the true binomial proportion based on this random sample of 1000 binomial trials and an observed proportion of 0.60, estimate the proportion of glaucoma risk reduction in women who eat the recommended servings of kale, collard greens, or carrots.
Answer to relevant QuestionsFind these critical values using Table 6 in Appendix B: a. t(21, 0.95) b. t(26, 0.975) c. t(27, 0.99) d. t(60, 0.025) a. If x successes result from a binomial experiment with n = 1000 and p = P(success) and the 95% confidence interval for the true probability of success is determined, what is the maximum value possible for the “maximum ...Find n for a 90% confidence interval for p with E = 0.02 using an estimate of p = 0.25 Determine the test criteria that would be used to test the following hypotheses when z is used as the test statistic and the classical approach is used The Committee of 200, a professional organization of preeminent women entrepreneurs and corporate leaders, reported the following: 60% of women MBA students say, “Businesses pay their executives too much money” and 50% ...
Post your question